9^x=(1/3)^(2x-4)

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Solution for 9^x=(1/3)^(2x-4) equation: 



9^x=(1/3)^(2x-4)

We move all terms to the left:

9^x-((1/3)^(2x-4))=0



Domain of the equation: 3)^(2x-4))!=0

x∈R



We add all the numbers together, and all the variables

9^x-((+1/3)^(2x-4))=0

We multiply all the terms by the denominator


9^x*3)^(2x+1-4))-((=0

We add all the numbers together, and all the variables

9^x*3)^(2x-3))-((=0

We add all the numbers together, and all the variables

9^x*3)^(2x=0

Wy multiply elements

27x^2=0

a = 27; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·27·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{54}=0$

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